## Monday, June 23, 2008

## Wednesday, June 4, 2008

### Simultaneous Equations

Algebra Problems

Let's discuss a particular technique used to solve simultaneous equations. Problem 1.

Eq.1 3x+2y=10

Eq.2 -6x+10y=4

Now, multiply the the first equation by 2.

Eq.1 2(3x+2y)=10(2) → 6x+4y=20

Eq.2 -6x+10y=4 → 6x+10y=4

When we add both equations, we are going to get

Eq.3 14y=24

Divide both sides by 14 and we get the following.

y=24/14 → y=12/7

We need to solve for x. We will then plug what we got for y into the first equation.

3x+2y=10 → 3x+2(12/7)=10 → 3x+24/7=10

Subtract 24/7 from both sides.

3x=46/7

Divide both sides by 3.

Therefore, we will get

x=46/21

Next time the topic of partial differential equations will be our focus.

Algebra equation

Let's discuss a particular technique used to solve simultaneous equations. Problem 1.

Eq.1 3x+2y=10

Eq.2 -6x+10y=4

Now, multiply the the first equation by 2.

Eq.1 2(3x+2y)=10(2) → 6x+4y=20

Eq.2 -6x+10y=4 → 6x+10y=4

When we add both equations, we are going to get

Eq.3 14y=24

Divide both sides by 14 and we get the following.

y=24/14 → y=12/7

We need to solve for x. We will then plug what we got for y into the first equation.

3x+2y=10 → 3x+2(12/7)=10 → 3x+24/7=10

Subtract 24/7 from both sides.

3x=46/7

Divide both sides by 3.

Therefore, we will get

x=46/21

Next time the topic of partial differential equations will be our focus.

Algebra equation

## Friday, May 16, 2008

### PME Tutoring

Hello, welcome to my blog. I will be discussing topics concerning mathematics, engineering, physics and programming. On Mondays, I will be asking my readers to ask me questions from their courses. I will select the most interesting questions and publish the answers.

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