Monday, June 23, 2008

Wednesday, June 4, 2008

Simultaneous Equations

Algebra Problems
Let's discuss a particular technique used to solve simultaneous equations. Problem 1.
Eq.1   3x+2y=10
Eq.2 -6x+10y=4

Now, multiply the the first equation by 2.
Eq.1  2(3x+2y)=10(2) →  6x+4y=20
Eq.2     -6x+10y=4        →  6x+10y=4

When we add both equations, we are going to get
Eq.3    14y=24

Divide both sides by 14 and we get the following.
          y=24/14   →   y=12/7

We need to solve for x. We will then plug what we got for y into the first equation.
         3x+2y=10 → 3x+2(12/7)=10 → 3x+24/7=10

Subtract 24/7 from both sides.
Divide both sides by 3.

Therefore, we will get


Next time the topic of partial differential equations will be our focus.

Friday, May 16, 2008

PME Tutoring

Hello, welcome to my blog. I will be discussing topics concerning mathematics, engineering, physics and programming. On Mondays, I will be asking my readers to ask me questions from their courses. I will select the most interesting questions and publish the answers.